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The presence of a cut-off frequency For any metal surface, there is a minimum frequency of incident radiation below which photocurrent does not occur. The value of this cut-off frequency for the photoelectric effect is a physical property of the metal: Different materials have different values of cut-off frequency.
In the case of visible light, increase in intensity is seen as increase in brightness. Increase in frequency, is seen as a change in color. Thus, the rate of flow of electrons increases and thus, the photocurrent increases linearly, with intensity of the incident radiation.
Ans: The incident frequency is 4.41 x 1014 Hz and the threshold frequency is 5.79 x 1014 Hz, and no photoelectron will be ejected. Example – 13: The photoelectric work function of a metal is 3 eV.
the threshold frequency for photoelectric effect for a metal surface is found to be 4.8 x 10^16 hz . the stopping potential required when the metal is iradicated by radiation of frequency 5.6×10^16 hz is.
The work function equals the threshold frequency times Planck’s constant. Planck’s constant is the proportionality constant that relates a photon’s frequency to its energy. Therefore, the constant is required to convert between the two quantities.
What is the frequency of a photon whose energy is 66.3 eV? v = 1.6 × 1016 Hz. 2.
Substituting h with its value in J⋅s and f with its value in hertz gives the photon energy in joules. Therefore, the photon energy at 1 Hz frequency is 6.62606957 × 10−34 joules or 4.135667516 × 10−15 eV. is used where h is Planck’s constant and the Greek letter ν (nu) is the photon’s frequency.
The correct option is (C) 16 × 10 +15 Hz.